JEE Mains · Maths · STD 12 - 13. probability
A number \(x\) is chosen at random from the set \(\{1, 2, 3, 4, .... , 100\}\) . Define the event: \(A =\) the chosen number \(x\) satisfies \(\frac{{(x - 10)(x - 50)}}{{(x - 30)}} \ge 0.\) Then \(P(A)\) is
- A \(0.71\)
- B \(0.70\)
- C \(0.51\)
- D \(0.20\)
Answer & Solution
Correct Answer
(A) \(0.71\)
Step-by-step Solution
Detailed explanation
Given \(\frac{(x-10)(x-50)}{(x-30)} \geq 0\) Let \(x \geq 10, x \geq 50\) equation will be true \(\forall x \geq 50\) as \(\left(\frac{x-50}{x-30}\right) \geq 0, \forall x \in[10,30)\) \(\begin{array}{c}{(x-10)(x-50)} \\ {x-30}\end{array} \geq 0 \forall x \in[10,30)\) Total…
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