ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

समीकरण \(e^{4 x}-e^{3 x}-4 e^{2 x}-e^{x}+1=0\) के वास्तविक मूलों की संख्या है

  1. A \(7\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(t^{4}-t^{3}-4 t^{2}-t+1=0, e^{x}=t>0\) \(\Rightarrow t^{2}-t-4-\frac{1}{t}+\frac{1}{t^{2}}=0\) \(\Rightarrow \alpha^{2}-\alpha-6=0, \alpha=t+\frac{1}{t} \geq 2\) \(\Rightarrow \alpha=3,-2(\text { reject })\) \(\Rightarrow t+\frac{1}{t}=3\) \(\Rightarrow\) The number of real…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app