ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

रेखाओं \((\sqrt{3}) kx + ky -4 \sqrt{3}=0\) तथा \(\sqrt{3} x - y -4(\sqrt{3}) k =0\) के प्रतिच्छेदन बिंदु का बिंदुपथ एक शांकव है, जिसकी उत्केन्द्रता है .......... |

  1. A \(0\)
  2. B \(2\)
  3. C \(4\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(K =\frac{4 \sqrt{3}}{\sqrt{3} x + y }=\frac{\sqrt{3} x - y }{4 \sqrt{3}}\) \(\Rightarrow 3 x ^{2}- y ^{2}=48\) \(\Rightarrow \frac{ x ^{2}}{16}-\frac{ y ^{2}}{48}=1\) Now, \(48=16\left( e ^{2}-1\right)\) \(\Rightarrow e =\sqrt{4}=2\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app