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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

रेखा \(\mathrm{ax}+\mathrm{by}=0,(\mathrm{a} \neq \mathrm{b})\) तथा वृत \(\mathrm{x}^2+\mathrm{y}^2-2 \mathrm{x}=0\) के प्रतिच्छेदन बिंदु \(\mathrm{A}(\alpha, 0)\) तथा \(\mathrm{B}(1, \beta)\) है। वृत्त, जिसका एक व्यास \(\mathrm{AB}\) है, का रेखा \(\mathrm{x}+\mathrm{y}+2=0\) में प्रतिबिम्ब है। :

  1. A \(x^2+y^2+5 x+5 y+12=0\)
  2. B \(x^2+y^2+3 x+5 y+8=0\)
  3. C \(x^2+y^2+3 x+3 y+4=0\)
  4. D \(x^2+y^2-5 x-5 y+12=0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(x^2+y^2+5 x+5 y+12=0\)

Step-by-step Solution

Detailed explanation

Only possibility \(\alpha=0, \beta=1\) \(\therefore\) equation of circle \(x ^2+ y ^2- x - y =0\) Image of circle in \(x+y+2=0\) is \(x^2+y^2+5 x+5 y+12=0\)
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