JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
The points of intersection of the line \(a x+b y=0\), \(( a \neq b )\) and the circle \(x ^2+ y ^2-2 x =0\) are \(A (\alpha, 0)\) and \(B (1, \beta)\). The image of the circle with \(AB\) as a diameter in the line \(x + y +2=0\) is:
- A \(x^2+y^2+5 x+5 y+12=0\)
- B \(x^2+y^2+3 x+5 y+8=0\)
- C \(x^2+y^2+3 x+3 y+4=0\)
- D \(x^2+y^2-5 x-5 y+12=0\)
Answer & Solution
Correct Answer
(A) \(x^2+y^2+5 x+5 y+12=0\)
Step-by-step Solution
Detailed explanation
Only possibility \(\alpha=0, \beta=1\) \(\therefore\) equation of circle \(x ^2+ y ^2- x - y =0\) Image of circle in \(x+y+2=0\) is \(x^2+y^2+5 x+5 y+12=0\)
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