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JEE Mains · Maths · STD 11 - 9. straight line

माना समीकरण \(\mathrm{x}(\mathrm{x}+2)(12-\mathrm{k})=2\) के मूल समान हैं। तब बिंदु \(\left(\mathrm{k}, \frac{\mathrm{k}}{2}\right)\) की रेखा \(3 x+4 y+5=0\) से दूरी __________ है।

  1. A \(15\)
  2. B \(5 \sqrt{3}\)
  3. C \(15 \sqrt{5}\)
  4. D \(12\)
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Answer & Solution

Correct Answer

(A) \(15\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \left(\mathrm{x}^2+2 \mathrm{x}\right)(12-\mathrm{k})=2 \\ & \lambda \mathrm{x}^2+2 \lambda \mathrm{x}-2=0 \quad \mathrm{k} \neq 12 \text { माना } 12-\mathrm{k}=\lambda \\ & \mathrm{D}=0 \\ & 4 \lambda^2+8 \lambda=0 \\ & \lambda=0 \text { या } \lambda=-2 \\ &…

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