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JEE Mains · Maths · STD 11 - 4.1 complex nubers

माना समीकरण \(x^2-\sqrt{6} x+3=0\) के मूल \(\alpha, \beta\) है तथा \(\operatorname{Im}(\alpha)>\operatorname{Im}(\beta)\) है। माना \(3\) से अभाज्य पूर्णांक \(a, b\) हैं तथा घन पूर्णांक \(n\) के लिए \(\frac{\alpha^{99}}{\beta}+\alpha^{98}=3^n(a+i b), i=\sqrt{-1}\) है। तो \(n+a+b\) = ...........

  1. A \(49\)
  2. B \(42\)
  3. C \(45\)
  4. D \(59\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(49\)

Step-by-step Solution

Detailed explanation

\( x^2-\sqrt{6} x+6=0 \) \( x=\frac{\sqrt{6} \pm i \sqrt{6}}{2}=\frac{\sqrt{6}}{2}(1 \pm i) \) \( \alpha=\sqrt{3}\left(e^{i \frac{\pi}{4}}\right), \beta=\sqrt{3}\left(e^{-i \frac{\pi}{4}}\right) \)…
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