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JEE Mains · Maths · STD 12 - 10. vector algebra

माना \(\hat{i}+\hat{j}, \hat{i}+\hat{k}\) तथा \(\hat{i}-\hat{j}, \hat{j}-\hat{k}\) द्वारा दिए गए दो समतलों की प्रतिच्छेदन रेखा के समांतर एक शून्येत्तर सदिश \(\vec{a}\) है। यदि सदिश \(\vec{a}\) तथा सदिश \(\vec{b}=2 \hat{i}-2 \hat{j}+\hat{k}\) के बीच कोण \(\theta\) है तथा \(\vec{a} \cdot \vec{b}=6\) है, तो क्रमित युग्म \((\theta,|\vec{a} \times \vec{b}|)\) बराबर है

  1. A \(\left(\frac{\pi}{4}, 3 \sqrt{6}\right)\)
  2. B \(\left(\frac{\pi}{3}, 3 \sqrt{6}\right)\)
  3. C \(\left(\frac{\pi}{3}, 6\right)\)
  4. D \(\left(\frac{\pi}{4}, 6\right)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\left(\frac{\pi}{4}, 6\right)\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ n }_1\) and \(\overrightarrow{ n }_2\) are normal vector to the plane \(\hat{i}+\hat{j}, \hat{i}+\hat{k}\) and \(\hat{i}-\hat{j} ; \hat{j}-\hat{k}\) respectively…
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