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JEE Mains · Maths · STD 11 - 4.1 complex nubers

यदि \(z \in \mathrm{C}\) का बिंदु पथ, इस प्रकार कि
\(\operatorname{Re}\left(\frac{z-1}{2 z+\mathrm{i}}\right)+\operatorname{Re}\left(\frac{\bar{z}-1}{2 \bar{z}-\mathrm{i}}\right)=2\)
\(r\) त्रिज्या और \((a, b)\) केंद्र का एक वृत्त है, तो \(\frac{15 a b}{r^2}\) = __________

  1. A 24
  2. B 12
  3. C 18
  4. D 16
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Answer & Solution

Correct Answer

(C) 18

Step-by-step Solution

Detailed explanation

\(\operatorname{Re}\left(\frac{z-1}{2 z+i}\right)+\operatorname{Re}\left(\frac{\bar{z}-1}{2 \bar{z}-i}\right)=2 \) \( \text {Here, } \frac{z-1}{2 z+i}=\left(\frac{\overline{\bar{z}-1}}{2 \bar{z}-i}\right)=2 \)…
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