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JEE Mains · Maths · STD 12 - 1. relation and function

माना \(f( x )= a ^{ x }( a >0)\) को \(f( x )=f_{1}( x )+f_{2}( x )\), के रूप में लिखा गया है जबकि \(f_{1}( x )\) एक सम फलन है और \(f_{2}( x )\) एक विषम फलन है, तो \(f_{1}( x + y )+f_{1}( x - y )\) बराबर है 

  1. A \(2{f_1}\left( x \right){f_2}\left( y \right)\)
  2. B \(2{f_1}\left( x \right){f_1}\left( y \right)\)
  3. C \(2{f_1}\left( {x + y} \right){f_2}\left( {x - y} \right)\)
  4. D \(2{f_1}\left( {x + y} \right){f_1}\left( {x - y} \right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2{f_1}\left( x \right){f_1}\left( y \right)\)

Step-by-step Solution

Detailed explanation

\({f_1}\left( x \right) = \frac{{{a^x} + {a^{ - x}}}}{2}\) and \({f_2}\left( x \right) = \frac{{{a^x} - {a^{ - x}}}}{2}\) \({f_1}\left( {x + y} \right) + {f_1}\left( {x - y} \right)\) \( = \frac{1}{2}\left( {{a^{x + y}} + {a^{ - x - y}} + {a^{x - y}} + {a^{ - x + y}}} \right)\)…
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