ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 6. Application of derivatives

\(\lambda\) के सभी वास्तविक मानों, जिनके लिए फलन \(f( x )=(1\) \(\left.-\cos ^{2} x\right) \cdot(\lambda+\sin x), x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)\), का केवल एक उच्चिष्ठ (maxima) तथा केवल एक निम्निष्ठ (minima) है, का समुच्चय है

  1. A \(\left(-\frac{1}{2}, \frac{1}{2}\right)-\{0\}\)
  2. B \(\left(-\frac{1}{2}, \frac{1}{2}\right)\)
  3. C \(\left(-\frac{3}{2}, \frac{3}{2}\right)\)
  4. D \(\left(-\frac{3}{2}, \frac{3}{2}\right)-\{0\}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\left(-\frac{3}{2}, \frac{3}{2}\right)-\{0\}\)

Step-by-step Solution

Detailed explanation

\(f(x)=\left(1-\cos ^{2} x\right)(\lambda+\sin x)\) \(x \in\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)\) \(f(x)=\lambda \sin ^{2} x+\sin ^{3} x\) \(f^{\prime}(x)=2 \lambda \sin x \cos x+3 \sin ^{2} x \cos x\) \(f^{\prime}(x)=\sin x \cos x(2 \lambda+3 \sin x)\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app