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JEE Mains · Maths · STD 12 - 11. three dimension geometry

माना दिक् अनुपात \(a,-4 a,-7\) की एक रेखा, दिक् अनुपात \(3,-1,2 b\) तथा \(b , a ,-2\) की रेखाओं के लंबवत् है। यदि रेखा \(\frac{ x +1}{ a ^2+ b ^2}=\frac{ y -2}{ a ^2- b ^2}=\frac{ z }{1}\) तथा समतल \(x - y + z =0\) का प्रतिच्छेदन बिन्दु \((\alpha, \beta, \gamma)\) है तो \(\alpha+\beta+\gamma\) बराबर है \(...........\)

  1. A \(20\)
  2. B \(10\)
  3. C \(30\)
  4. D \(40\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

\(( a ,-4 a ,-7) \perp\) to \((3,-1,2 b )\) \(a =2 b\) \(( a ,-4 a ,-7) \perp\) to \(( b , a ,-2)\) \(3 a +4 a -14 b =0\) \(ab -4 a ^{2}+14=0\) From Equations \((i)\) and \((ii)\) \(2 b ^{2}-16 b ^{2}+14=0\) \(b ^{2}=1\) \(a ^{2}=4 b ^{2}=4\)…
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