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JEE Mains · Maths · STD 12 - 10. vector algebra

माना दो सदिश \(\vec{a}\) तथा \(\vec{b}\) इस प्रकार है कि \(|\vec{b}|=1\) तथा \(|\vec{b} \times \vec{a}|=2\) हैं। तो \(|(\vec{b} \times \vec{a})-\vec{b}|^2\) = ...........

  1. A \(3\)
  2. B \(5\)
  3. C \(1\)
  4. D \(4\)
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Correct Answer

(B) \(5\)

Step-by-step Solution

Detailed explanation

\(|\vec{b}|=1 \&|\vec{b} \times \vec{a}|=2 \) \((\vec{b} \times \vec{a}) \cdot \vec{b}=\vec{b} \cdot(\vec{b} \times \vec{a})=0 \) \(|(\vec{b} \times \vec{a})-\vec{b}|^2=|\vec{b} \times \vec{a}|^2+|\vec{b}|^2 \) \(=4+1=5\)
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