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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

माना दीर्घवृत्त, \(\frac{ x ^{2}}{25}+\frac{ y ^{2}}{ b ^{2}}=1( b <5)\) तथा अतिपरवलय \(\frac{x^{2}}{16}-\frac{y^{2}}{b^{2}}=1\) की उत्केन्द्रताएँ क्रमशः \(e_{1}\) तथा \(e_{2}\) है और \(e_{1} e_{2}\) \(=1\) है। यदि दीर्घवृत्त और अतिपरवलय के नाभिकेन्दों के बीच की दूरीयाँ क्रमशः \(\alpha\) तथा \(\beta\) हैं, तो क्रमित युग्म \((\alpha, \beta)\) बराबर है

  1. A \((8,10)\)
  2. B \((8,12)\)
  3. C \(\left(\frac{20}{3}, 12\right)\)
  4. D \(\left(\frac{24}{5}, 10\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \((8,10)\)

Step-by-step Solution

Detailed explanation

For ellipse \(\frac{x^{2}}{25}+\frac{y^{2}}{b^{2}}=1 \quad(b<5)\) Let e \(_{1}\) is eccentricity of ellipse \(\therefore \quad b^{2}=25\left(1-e_{1}^{2}\right) \ldots \ldots .(1)\) Again for hyperbola \(\frac{x^{2}}{16}-\frac{y^{2}}{b^{2}}=1\) Let \(e _{2}\) is eccentricity of…
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