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JEE Mains · Maths · STD 12 - 9. differential equations

माना अवकल समीकरण \((x \cos x) d y+(x y \sin x+\) \(\mathrm{y} \cos \mathrm{x}-1) \mathrm{dx}=0,0<\mathrm{x}<\frac{\pi}{2}\) का हल \(\mathrm{y}=\mathrm{y}(\mathrm{x})\) है। यदि \(\frac{\pi}{3} \mathrm{y}\left(\frac{\pi}{3}\right)=\sqrt{3}\) है, तो \(\left|\frac{\pi}{6} \mathrm{y}^{\prime \prime}\left(\frac{\pi}{6}\right)+2 \mathrm{y}^{\prime}\left(\frac{\pi}{6}\right)\right|\) का मान है__________

  1. A \(4\)
  2. B \(6\)
  3. C \(8\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2\)

Step-by-step Solution

Detailed explanation

\((x \cos x) d y+(x y \sin x+y \cos x-1) d x=0\), \(0 < x < \frac{\pi}{2}\) \(\frac{d y}{d x}+\left(\frac{x \sin x+\cos x}{x \cos x}\right) y=\frac{1}{x \cos x}\) \(I F=x \sec x\) \(y \cdot x \sec x=\int \frac{x \sec x}{x \cos x} d x=\tan x+c\)…
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