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JEE Mains · Maths · STD 12 - 10. vector algebra

माना \(\vec{a}=3 \hat{i}+2 \hat{j}+\hat{k}, \vec{b}=2 \hat{i}-\hat{j}+3 \hat{k}\) तथा सदिश \(\vec{c}\) इस प्रकार है कि \((\vec{a}+\vec{b}) \times \vec{c}=2(\vec{a} \times \vec{b})+24 \hat{j}-6 \hat{k}\) तथा \((\vec{a}-\vec{b}+\hat{i}) \cdot \vec{c}=-3\) हैं। तो \(|\vec{c}|^2\) = ...........

  1. A \(30\)
  2. B \(38\)
  3. C \(35\)
  4. D \(40\)
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Correct Answer

(B) \(38\)

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\begin{aligned} & (\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}) \times \overrightarrow{\mathrm{c}}=2(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}})+24 \hat{\mathrm{j}}-6 \hat{\mathrm{k}} \\ & (5 \hat{\mathrm{i}}+\hat{\mathrm{j}}+4 \hat{\mathrm{k}})…

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