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JEE Mains · Maths · STD 11 - 8. sequence and series

माना \(a_{1}, a_{2}, a_{3}, \ldots\) एक \(A.P.\) है। यदि \(\frac{a_{1}+a_{2}+\ldots+a_{10}}{a_{1}+a_{2}+\ldots+a_{p}}=\frac{100}{p^{2}}, p \neq 10\) है, तो \(\frac{a_{11}}{a_{10}}\) बराबर है

  1. A \(\frac{19}{21}\)
  2. B \(\frac{100}{121}\)
  3. C \(\frac{21}{19}\)
  4. D \(\frac{121}{100}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{21}{19}\)

Step-by-step Solution

Detailed explanation

\(\frac{\frac{10}{2}\left(2 \mathrm{a}_{1}+9 \mathrm{~d}\right)}{\frac{\mathrm{p}}{2}\left(2 \mathrm{a}_{1}+(\mathrm{p}-1) \mathrm{d}\right)}=\frac{100}{\mathrm{p}^{2}}\)…
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