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JEE Mains · Maths · STD 12 - 9. differential equations

मान लीजिए \(f(x)=x-1\) और \(g(x)=e^x\) जहाँ \(x \in \mathbb{R}\) के लिए। यदि \(\frac{d y}{d x}=\left(e^{-2 \sqrt{x}} g(f(f(x)))-\frac{y}{\sqrt{x}}\right), y(0)=0\), तब \(y(1)\) ___ है।

  1. A \(\frac{1-e^2}{e^4}\)
  2. B \(\frac{2 e-1}{e^3}\)
  3. C \(\frac{e-1}{e^4}\)
  4. D \(\frac{1-e^3}{e^4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{e-1}{e^4}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & f(x)=x-1 \\ & f(f(x))=f(x)-1=x-1-1=x-2 \\ & g(f(f(x)))=e^{x-2} \\ & \therefore \frac{d y}{d x}=e^{-2 \sqrt{x}} \times e^{x-2}-\frac{1}{\sqrt{x}} y \\ & \frac{d y}{d x}+\frac{1}{\sqrt{x}} y=e^{x-2 \sqrt{x}-2} \text { which is L.D.E } \\ & \text { I.F. }=e^{\int…

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