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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

जब-जब \(\alpha\) समीकरण \(x ^{2}+ ax + b =0\), का एक मूल है, \(\alpha^{2}-2\) भी इस समीकरण का एक मूल है। इसके लिए वास्ताविक संख्याओं के युग्मों \(( a , b )\) की संख्या है

  1. A \(6\)
  2. B \(2\)
  3. C \(4\)
  4. D \(8\)
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Answer & Solution

Correct Answer

(A) \(6\)

Step-by-step Solution

Detailed explanation

Consider the equation \(x^{2}+a x+b=0\) If has two roots (not necessarily real \(\alpha \, \& \beta\) ) Either \(\alpha=\beta\) or \(\alpha \neq \beta\) Case \((1)\) If \(\alpha=\beta\), then it is repeated root. Given that \(\alpha^{2}-2\) is also a root So,…
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