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JEE Mains · Maths · STD 11 - 7. binomial theoram

\(\alpha>0, \beta>0\) ऐसा हो कि \(\alpha^{3}+\beta^{2}=4\) हो। यदि \(\left(\alpha x^{\frac{1}{9}}+\beta x^{-\frac{1}{6}}\right)^{10}\) के द्विपदीय विस्तार में \(x\) से स्वतंत्र पद का अधिकतम मान \(10 k\) है, तो \(k\) बराबर है

  1. A \(176\)
  2. B \(336\)
  3. C \(352\)
  4. D \(84\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(336\)

Step-by-step Solution

Detailed explanation

Let \(t_{\mathrm{r}}+1\) denotes \(\mathrm{r}+1 \mathrm{th}\) term of \(\left(\alpha \mathrm{x}^{\frac{1}{9}}+\beta \mathrm{x}^{-\frac{1}{6}}\right)^{10}\)…
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