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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

एक प्रथम कोटि की अभिक्रिया के \(90 \%\) पूर्ण होने में लगा समय इसके अर्द्ध-आयु काल का ' \(x\) ' गुना है। ' \(x\) ' का मान है- (दिया है: \(\ln 10=2.303\) एवं \(\log 2=0.3010\) )

  1. A \(1.12\)
  2. B \(2.43\)
  3. C \(3.32\)
  4. D \(33.31\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3.32\)

Step-by-step Solution

Detailed explanation

Given \(t _{0.90}= t _{0.90}= xt _{1 / 2}\) First order rate constant \(K =\frac{\ln 2}{ t _{1 / 2}}=\frac{1}{ xt _{1 / 2}} \ln \frac{ A _{0}}{ A _{0}- A _{0} \times \frac{90}{100}}\) \(\frac{\ln 2}{ t _{1 / 2}}=\frac{\ln 10}{ xt _{1 / 2}}\)…
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