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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

\(x^2-5 a x+1=0\) અને \(x^2-a x-5=0\) ને સામાન્ય વાસ્તવિક બીજ હોય તેવ વાસ્તવિક સંખ્યા \(a > 0\) નું મૂલ્ય જો \(\frac{3}{\sqrt{2 \beta}}\) હોય, તો \(\beta=..........\)

  1. A \(11\)
  2. B \(13\)
  3. C \(12\)
  4. D \(14\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(13\)

Step-by-step Solution

Detailed explanation

`Two equations have common root \(\therefore(4 a)(26 a)=(-6)^2=36\) \(\Rightarrow a^2=\frac{9}{26} \quad \therefore a=\frac{3}{\sqrt{26}} \Rightarrow \beta=13\)
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