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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

સમીકરણ  \({x^2}\, + \,\left| {2x - 3} \right|\, - \,4\, = \,0,\) ના ઉકેલો નો સરવાળો ...... થાય. 

  1. A \(2\)
  2. B \(-2\)
  3. C \(\sqrt 2\)
  4. D \(-\sqrt 2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt 2\)

Step-by-step Solution

Detailed explanation

\({x^2} + |2x - 3| - 4 = 0\) \(|2 x-3|=\left\{\begin{array}{ccc}{(2 x-3)} & {\text { if }} & {x>\frac{3}{2}} \\ {-(2 x-3)} & {\text { if }} & {x<\frac{3}{2}}\end{array}\right.\) for \(x>\frac{3}{2},\) \(x^{2}+2 x-3-4=0\) \(x^{2}+2 x-7=0\) \(x=\frac{-2 \pm \sqrt{4+28}}{2}\)…
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