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JEE Mains · Maths · STD 11 - Trigonometrical equations

સમીકરણ \(\cos ^2 2 x-2 \sin ^4 x-2 \cos ^2 x=\lambda\) ને વાસ્તવિક ઉકેલ \(x\) હોય તેવી \(\lambda\) ની તમામ કિંમતોનો ગણ \(...........\) છે.

  1. A \([-2,-1]\)
  2. B \(\left[-2,-\frac{3}{2}\right]\)
  3. C \(\left[-1,-\frac{1}{2}\right]\)
  4. D \(\left[-\frac{3}{2},-1\right]\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\left[-\frac{3}{2},-1\right]\)

Step-by-step Solution

Detailed explanation

\(\lambda=\cos ^2 2 x-2 \sin ^4 x-2 \cos ^2 x\) \(\text { convert all in to } \cos x \text {. }\) \(\lambda=\left(2 \cos ^2 x-1\right)^2-2\left(1-\cos ^2 x\right)^2-2 \cos ^2 x\) \(=4 \cos ^4 x-4 \cos ^2 x+1-2\left(1-2 \cos ^2 x+\cos ^4 x\right)-\) \(2 \cos ^2 x\)…
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