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JEE Mains · Maths · STD 12 - 10. vector algebra

સદીશ \(\vec{a}=2 \hat{i}+\hat{j}-2 \hat{k}\) અને \(\vec{b}=\hat{i}+\hat{j} \) આપેલ છે. જો સદીશ \(\vec{c}\) એ આપેલ છે કે જેથી \(\vec{a} \cdot \vec{c}=|\vec{c}|,|\vec{c}-\vec{a}|=2 \sqrt{2}\) થાય છે અને  \((\vec{a} \times \vec{b})\) અને \(\vec{c}\) વચ્ચેનો ખૂણો  \(\frac{\pi}{6}\) હોય તો \(|(\vec{a} \times \vec{b}) \times \vec{c}|\) ની કિમંત મેળવો.

  1. A \(\frac{2}{3}\)
  2. B \(4\)
  3. C \(3\)
  4. D \(\frac{3}{2}\)
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Answer & Solution

Correct Answer

(D) \(\frac{3}{2}\)

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Detailed explanation

\(|\vec{a}|=a ; \vec{a} \cdot \vec{c}=c\) \(\text { Now }|\vec{c}-\vec{a}|=2 \sqrt{2}\) \(\Rightarrow c^{2}+a^{2}-2 \vec{c} \cdot \vec{a}=8\) \(\Rightarrow c^{2}+9-2(c)=8\) \(\Rightarrow C^{2}-2 C+1=0 \Rightarrow C=1 \Rightarrow|\vec{c}|=1\) Also,…
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