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JEE Mains · Maths · STD 12 - 7.2 definite integral

ધારો કે \(f:(0, \infty) \rightarrow \mathbf{R}\) એ દ્વિ-વિકલનીય વિધેય છે. જો કોઈક \(\mathrm{a} \neq 0\) માટે, \(\int_0^1 f(\lambda x) \mathrm{d} \lambda=\mathrm{a} f(x)\), \(f(1)=1\) અને \(f(16)=\frac{1}{8}\) હોય, તો \(16-f^{\prime}\left(\frac{1}{16}\right)\) = ___

  1. A 110
  2. B 111
  3. C 112
  4. D 113
Verified Solution

Answer & Solution

Correct Answer

(C) 112

Step-by-step Solution

Detailed explanation

Given, \(\int_0^1 f(\lambda x) d \lambda=a f(x)\) Let \(\lambda x=u\) \(d \lambda=\frac{1}{x} d u\) \(\therefore\) From (1) \(\frac{1}{x} \int_0^x f(u) d u=a f(x)\) \(\Rightarrow \int_0^x f(u) d u=\operatorname{axf}(x)\) Differentiate both sides…
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