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JEE Mains · Maths · STD 12 - 8. Application and integration

પરવલય \(y = x^2 + 2\) અને રેખાઓ \(y = x + 1, x = 0\) અને  \(x = 3\) દ્વારા  આવૃત પ્રદેશ નું ક્ષેત્રફળ મેળવો .

  1. A \(\frac{15}{4}\)
  2. B \(\frac{21}{2}\)
  3. C \(\frac{17}{4}\)
  4. D \(\frac{15}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{15}{2}\)

Step-by-step Solution

Detailed explanation

Required area \(\int\limits_0^3 {\left( {\left( {{x^2} + 2} \right) - (x + 1)} \right)} dx\) \( = \int\limits_0^3 {\left( {{x^2} - x + 1} \right)dx = \frac{{15}}{2}} \)
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