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JEE Mains · Maths · STD 12 - 11. three dimension geometry

બિંદુ \((2,3,5)\) નું રેખા \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) ની સાપેક્ષે પ્રતિબિંબ બિંદુ \((\alpha, \beta, \gamma)\) છે. તો \(2 \alpha+3 \beta+\) \(4 \gamma =\) ...........

  1. A \(32\)
  2. B \(33\)
  3. C \(31\)
  4. D \(34\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(33\)

Step-by-step Solution

Detailed explanation

\(\because \overrightarrow{\mathrm{PR}} \perp(2,3,4) \) \(\therefore \overrightarrow{\mathrm{PR}} \cdot(2,3,4)=0 \) \((\alpha-2, \beta-3, \gamma-5) \cdot(2,3,4)=0 \) \(\Rightarrow 2 \alpha+3 \beta+4 \gamma=4+9+20=33\)
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