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JEE Mains · Maths · STD 11 - 4.1 complex nubers

જો \(z\) સંકર સંખ્યા છે કે જેથી \(\left|\frac{z-i}{z+2 i}\right|=1\) અને  \(|z|=\frac{5}{2} \cdot\) હોય તો \(|z+3 i|\) મેળવો.

  1. A \(\sqrt{10}\)
  2. B \(2 \sqrt{3}\)
  3. C \(\frac{7}{2}\)
  4. D \(\frac{15}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{7}{2}\)

Step-by-step Solution

Detailed explanation

\(\left|\frac{z-i}{z+2 i}\right|=1\) \(\Rightarrow|z-i|=|z+2 i|\) \(\Rightarrow \quad z\) lies on perpendicular bisector of \((0,1)\) and \((0,-2)\) \(\Rightarrow \quad \operatorname{Im} z=-\frac{1}{2}\) Let \(z=x-\frac{i}{2}\)…
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