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JEE Mains · Maths · STD 11 - 4.1 complex nubers

\(|z|\), जहाँ \(z\) एक सम्मिश्र संख्या है, का न्यूनतम मान, जो असमिका exp, \(\left(\frac{(|z|+3)(|z|-1)}{|| z|+1|} \log _{e} 2\right) \geq \log _{\sqrt{2}}|5 \sqrt{7}+9 i|\) \(i =\sqrt{-1}\) को सन्तुष्ट करता है

  1. A \(3\)
  2. B \(\sqrt{5}\)
  3. C \(2\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(3\)

Step-by-step Solution

Detailed explanation

\(\exp \left(\frac{(|z|+3)(|z|-1)}{|| z|+1|} \ell\right.\) n \(\left.2\right) \geq \log _{\sqrt{2}}|5 \sqrt{7}+9 i|\) \(\Rightarrow \quad 2^{\frac{(|z|+3)(|z|-1)}{(|z|+1)} \geq \log _{\sqrt{2}}(16)}\) \(\Rightarrow \quad 2^{\frac{(|z|+3)(|z|-1)}{(|z|+1)} \geq 2^{3}}\)…
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