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JEE Mains · Maths · STD 11 - 4.1 complex nubers

જો \(z = \frac{{\sqrt 3 }}{2} + \frac{i}{2}\,\,\,\left( {i = \sqrt { - 1} } \right)\) હોય તો \({\left( {1 + iz + {z^5} + i{z^8}} \right)^9}\)ની કિમત મેળવો. 

  1. A \(-1\)
  2. B \(1\)
  3. C \((-1 + 2i)^9\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-1\)

Step-by-step Solution

Detailed explanation

\(z=\frac{\sqrt{3}+i}{2}=e^{\frac{i \pi}{6}}\) \(\left(1+i z+z^{5}+i z^{8}\right)^{9}\) \(=\left(1+\mathrm{e}^{\mathrm{i} \pi / 2} \mathrm{e}^{\mathrm{i} \pi / 6}+\mathrm{e}^{\mathrm{i} 5 \pi / 6}+\mathrm{e}^{\mathrm{i} \pi / 2} \mathrm{e}^{\mathrm{i} 8 \pi / 6}\right)^{9}\)…
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