ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 5. continuity and differentiation

વિધેય \(f \,[-3,3]\) પર \(f(x)=\left\{\begin{array}{cc}\min \left\{|x|, 2-x^{2}\right\} & , \quad-2 \leq x \leq 2 \\ {[|x|]} & , \quad 2<|x| \leq 3\end{array}\right.\) વડે વ્યાખ્યાયીત છે, જ્યાં\([x]\) મહત્તમ પૂર્ણાંક \(\leq x\) દર્શાવે છે. \((-3,3)\) માં \(f\) વિકલનીય ન થાય તેવા બિંદુઓની સંખ્યા ...... છે.

  1. A \(10\)
  2. B \(2\)
  3. C \(5\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5\)

Step-by-step Solution

Detailed explanation

\(f(x)=\left\{\begin{array}{cc}\min \left\{|x|, 2-x^{2}\right\} & , \quad-2 \leq x \leq 2 \\ {[|x|]} & , \quad 2<|x| \leq 3\end{array}\right.\) \(\Rightarrow x \in[-3,-2) \cup(2,3]\) Number of points of non-differentiability in \((-3,3)=5\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app