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JEE Mains · Maths · STD 11 - 4.1 complex nubers

જો\(z^{2}+z+1=0, z \in C\) હોય,તો \(\left|\sum_{n=1}^{15}\left(z^{n}+(-1)^{n} \frac{1}{z^{n}}\right)^{2}\right|=\dots\dots\dots\dots\)

  1. A \(1\)
  2. B \(3\)
  3. C \(2\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2\)

Step-by-step Solution

Detailed explanation

\(z ^{2}+ z +1=0 \Rightarrow z = w , w ^{2}\) \(\left|\sum_{n=1}^{15}\left(z^{n}+(-1) \frac{1}{z^{n}}\right)^{2}\right|=\left|\sum_{n=1}^{15}\left(z^{2 n}+\frac{1}{z^{2 n}}+2(-1)^{n}\right)\right|\) \(=\left|\sum_{n=1}^{15} w^{2 n}+\frac{1}{w^{2 n}}+2(-1)^{n}\right|\)…
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