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JEE Mains · Maths · STD 12 - 6. Application of derivatives

જો વક્ર \(y=x+\sin y\) નો બિંદુ \((a, b)\) આગળનો સ્પર્શક બિંદુઓ \(\left(0, \frac{3}{2}\right)\) અને \(\left(\frac{1}{2}, 2\right),\) ને જોડતી રેખાને સમાંતર હોય તો 

  1. A \(b=a\)
  2. B \(\mathrm{b}=\frac{\pi}{2}+\mathrm{a}\)
  3. C \(|b-a|=1\)
  4. D \(|\mathrm{a}+\mathrm{b}|=1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(|b-a|=1\)

Step-by-step Solution

Detailed explanation

Slope of tangent to the curve \(y=x+\sin y\) at \((a, b)\) is \(\frac{2-\frac{3}{2}}{\frac{1}{2}-0}=1\) \(\left.\Rightarrow \quad \frac{\mathrm{dy}}{\mathrm{dx}}\right]_{\mathrm{x}=\mathrm{a}}=1\) \(\frac{d y}{d x}=1+\cos y \cdot \frac{d y}{d x}(\) from equation of curve \()\)…
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