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JEE Mains · Maths · STD 12 - 6. Application of derivatives

જો વિધેય \(f(x)=\left(\frac{1}{x}\right)^{2 x} ; x>0\) એ \(x=\frac{1}{\mathrm{e}}\) આગળ મહત્તમ મૂલ્ય ધારણ કરે, તો :

  1. A  \(\mathrm{e}^\pi<\pi^{\mathrm{e}}\)
  2. B  \(\mathrm{e}^{2 \pi}<(2 \pi)^{\mathrm{e}}\)
  3. C \(\mathrm{e}^\pi>\pi^{\mathrm{e}}\)
  4. D \((2 \mathrm{e})^\pi>\pi^{(2 \mathrm{e})}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{e}^\pi>\pi^{\mathrm{e}}\)

Step-by-step Solution

Detailed explanation

Let \(y=\left(\frac{1}{x}\right)^{2 x}\) \( \ell \text { ny }=2 x \ell n\left(\frac{1}{x}\right) \) \( \ell n y=-2 x \ell n x \) \( \frac{1}{y} \frac{d y}{d x}=-2(1+\ell n x)\) for \(\mathrm{x}>\frac{1}{\mathrm{e}} \mathrm{f}^{\mathrm{n}}\) is decreasing so, \( \mathrm{e}<\pi \)…
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