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JEE Mains · Maths · STD 12 - 7.2 definite integral

જો સંકલન \(\int_{0}^{10} \frac{[\sin 2 \pi x ]}{ e ^{ x -[ x ]}} dx =\alpha e ^{-1}+\beta e ^{-\frac{1}{2}}+\gamma\) આપેલ છે કે જ્યાં  \(\alpha, \beta, \gamma\) એ પૃણાંક છે અને \([ x ]\) એ મહતમ પૃણાંક છે  તો  \(\alpha+\beta+\gamma\) ની કિમંત મેળવો.

  1. A \(0\)
  2. B \(20\)
  3. C \(25\)
  4. D \(10\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0\)

Step-by-step Solution

Detailed explanation

Let \(I=\int_{0}^{10} \frac{[\sin 2 \pi x ]}{ e ^{ x -[ x ]}} dx =\int_{0}^{10} \frac{[\sin 2 \pi x ]}{ e ^{\{ x \}}} dx\) Function \(f ( x )=\frac{[\sin 2 \pi x ]}{ e ^{\{ x \}}}\) is periodic with period \('1'\) Therefore…
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