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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

જો સમીકરણોની સંહતિ
\(\begin{aligned} & (\lambda-1) x+(\lambda-4) y+\lambda z=5 \\ & \lambda x+(\lambda-1) y+(\lambda-4) z=7 \\ & (\lambda+1) x+(\lambda+2) y-(\lambda+2) z=9\end{aligned}\)
અનંત ઉકેલો ધરાવે છે, તો \(\lambda^2+\lambda\) = ___

  1. A \(6\)
  2. B \(10\)
  3. C \(20\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(12\)

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Detailed explanation

\(\begin{aligned} & (\lambda-1) x+(\lambda-4) y+\lambda z=5 \\ & \lambda x+(\lambda-1) y+(\lambda-4) z=7 \\ & (\lambda+1) x+(\lambda+2) y-(\lambda+2) z=9 \end{aligned}\) અનંત ઉકેલો માટે…
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