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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

જો સમીકરણ સંહિતા  \(x+y+z=2\) \(2 x+4 y-z=6\) \(3 x+2 y+\lambda z=\mu\) ને અનંત ઉકેલો હોય તો 

  1. A \(\lambda-2 \mu=-5\)
  2. B \(2 \lambda-\mu=5\)
  3. C \(2 \lambda+\mu=14\)
  4. D \(\lambda+2 \mu=14\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2 \lambda+\mu=14\)

Step-by-step Solution

Detailed explanation

For infinite solutions \(\Delta=\Delta_{ x }=\Delta_{ y }=\Delta_{ z }=0\) Now \(\Delta=0 \Rightarrow\left|\begin{array}{ccc}1 & 1 & 1 \\ 2 & 4 & -1 \\ 3 & 2 & \lambda\end{array}\right|=0\) \(\Rightarrow \lambda=\frac{9}{2}\)…
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