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JEE Mains · Maths · STD 12 - 11. three dimension geometry

ધારોકે બિંદુ \(P(3,-2,-9)\) માંથી,બિંદુઓ \((-1,-2,-3),(9,3,4),(9,-2,1)\) માંથી પસાર થતા સમતલ પરનો લંબપાદ \(Q(\alpha, \beta, \gamma)\) છે.તો \(Q\) નું ઉગમબિંદુ થી અંતર \(........\) છે.

  1. A \(\sqrt{29}\)
  2. B \(\sqrt{35}\)
  3. C \(\sqrt{42}\)
  4. D \(\sqrt{38}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt{42}\)

Step-by-step Solution

Detailed explanation

\(P (3,-2,-9)\) Equation of plane through \(A,B,C.\) \(\left|\begin{array}{ccc}x+1 & y+2 & z+3 \\10 & 5 & 7 \\10 & 0 & 4\end{array}\right|=0\) \(2 x+3 y-5 z-7=0\) Foot of \(I ^{ r }\) of \(P (3,-2,-9)\) is \(\frac{x-3}{2}=\frac{y+2}{3}=\frac{z+9}{-5}=-\frac{(6-6+45-7)}{4+9+25}\)…
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