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JEE Mains · Maths · STD 12 - 11. three dimension geometry

જો રેખાઓ  \(\frac{x-1}{2}=\frac{2-y}{-3}=\frac{z-3}{\alpha}\) અને  \(\frac{x-4}{5}=\frac{y-1}{2}=\frac{z}{\beta}\) છેદતી હોય તો  \(8 \alpha \beta\) માં મૂલ્યની ન્યૂનતમ કિમંત  \(...............\) થાય.

  1. A \(16\)
  2. B \(14\)
  3. C \(18\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(18\)

Step-by-step Solution

Detailed explanation

If the lines \(\frac{x-1}{2}=\frac{2-y}{-3}=\frac{z-3}{\alpha}\) And \(\frac{x-4}{5}=\frac{y-1}{2}=\frac{z}{\beta}\) intersect Point on first line \((1,2,3)\) and point on second line \((4,1,0)\). Vector joining both points is \(-3 \hat{i}+\hat{j}+3 \hat{k}\) Now vector along…
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