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JEE Mains · Maths · STD 11 - 9. straight line

જો રેખા \(L\)નો \(x-\) અંત:ખંડ રેખા \(3x + 4y = 12\) ના \(x-\) અંત:ખંડ કરતાં બમણો હોય અને   રેખા \(L\)નો \(y-\) અંત:ખંડ તે જ રેખા કરતાં અડધો હોય તો રેખા \(L\)નો  ઢાળ મેળવો. 

  1. A \(-3\)
  2. B \(-3/8\)
  3. C \(-3/2\)
  4. D \(-3/16\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-3/16\)

Step-by-step Solution

Detailed explanation

Given line \(3x+4y=12\) can be rewritten as \(\frac{{3x}}{{12}} + \frac{{4y}}{{12}} = 1 \Rightarrow \frac{x}{4} + \frac{y}{3} = 1\) \( \Rightarrow \) \(x\) -intercept \(=4\) and \(y\)-intercept \(=3\) Let the required line be \(L:\frac{x}{a} + \frac{y}{b} = 1\) where \(a=x\)…
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