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JEE Mains · Maths · STD 12 - 7.2 definite integral

જો \(f\left( x \right) = \frac{{2 - x\,\cos \,x}}{{2 + x\,\cos \,x}}\) અને  \(g\left( x \right) = {\log _e}\,x\), \(\left( {x > 0} \right)\) તો  \(\int\limits_{\frac{{ - \pi }}{4}}^{\frac{\pi }{4}} {g\left( {f\left( x \right)} \right)} dx\) મેળવો.

  1. A \({\log _e}\,1\)
  2. B \({\log _e}\,2\)
  3. C \({\log _e}\,e\)
  4. D \({\log _e}\,3\)
Verified Solution

Answer & Solution

Correct Answer

(A) \({\log _e}\,1\)

Step-by-step Solution

Detailed explanation

\(g(f(x))=\ln (f(x))=\ln \left(\frac{2-x \cdot \cos x}{2+x \cdot \cos x}\right)\) \(\therefore \quad \mathrm{I}=\int_{0}^{\pi / 4}\left(\ln \left(\frac{2-x \cdot \cos x}{2+x \cdot \cos x}\right)+\ell\left(\frac{2+x \cdot \cos x}{2-x \cdot \cos x}\right)\right) d x\)…
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