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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

જો \(\alpha \) અને \(\beta \) એ દ્રીઘાત સમીકરણ \(x^2 - 2x + 2 = 0\)ના ઉકેલગણ હોય તો \(n\) કઈ ન્યૂનતમ કિમત માટે \({\left( {\frac{\alpha }{\beta }} \right)^n} = 1\) થાય?

  1. A \(4\)
  2. B \(2\)
  3. C \(5\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(4\)

Step-by-step Solution

Detailed explanation

\((x-1)^{2}+1=0 \Rightarrow x=1+i, 1-i\) \(\therefore\left(\frac{\alpha}{\beta}\right)^{n}=1 \Rightarrow(\pm i)^{n}=1\) \(n\) (least natural number) \(=4\)
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