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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

જો \(A=\left\{(x, y) \in R \times R \mid 2 x^{2}+2 y^{2}-2 x-2 y=1\right\}\) ; \(B=\left\{(x, y) \in R \times R \mid 4 x^{2}+4 y^{2}-16 y+7=0\right\}\) અને \(C=\left\{(x, y) \in R \times R \mid x^{2}+y^{2}-4 x-2 y+5 \leq r^{2}\right\}\) હોય તો \(|r|\) ની ન્યૂનતમ કિમંત મેળવો કે જેથી \(A \cup B \subseteq C\) થાય.

  1. A \(\frac{3+\sqrt{10}}{2}\)
  2. B \(1+\sqrt{5}\)
  3. C \(\frac{2+\sqrt{10}}{2}\)
  4. D \(\frac{3+2 \sqrt{5}}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{3+2 \sqrt{5}}{2}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{S}_{1}: \mathrm{x}^{2}+\mathrm{y}^{2}-\mathrm{x}-\mathrm{y}-\frac{1}{2}=0 ; \mathrm{C}_{1}\left(\frac{1}{2}, \frac{1}{2}\right)\) \(\mathrm{r}_{1}=\sqrt{\frac{1}{4}+\frac{1}{4}+\frac{1}{2}}=1\)…
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