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JEE Mains · Maths · STD 12 - 10. vector algebra

ધારોકે \(\lambda \in Z , \vec{a}=\lambda \hat{i}+\hat{j}-\hat{k}\) અને \(\vec{b}=3 \hat{i}-\hat{j}+2 \hat{k}\). ધારોકે \(\vec{c}\) એવો સદિશ છે કે જેથી \((\vec{a}+\vec{b}+\vec{c}) \times \vec{c}=\overrightarrow{0}, \vec{a} \cdot \vec{c}=-17\) અને \(\vec{b} \cdot \vec{c}=-20\).તો \(|\vec{c} \times(\lambda \hat{i}+\hat{j}+\hat{k})|^2\) \(=........\)

  1. A \(62\)
  2. B \(46\)
  3. C \(53\)
  4. D \(49\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(46\)

Step-by-step Solution

Detailed explanation

\((\vec{a}+\vec{b}+\overrightarrow{ c }) \times \overrightarrow{ c }=0\) \((\vec{a}+\vec{b}) \times \vec{c}=0\) \(\overrightarrow{ c }=\alpha(\overrightarrow{ a }+\overrightarrow{ b })=\alpha(\lambda+3) \hat{ i }+\alpha \hat{ k }\)…
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