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JEE Mains · Maths · STD 11 - 4.1 complex nubers

ધારોકે \(S=\left\{z \in C-\{i, 2 i\}: \frac{z^2+8 i z-15}{z^2-3 i z-2} \in R \right\}\).જો \(\alpha-\frac{13}{11} i \in S , \alpha \in R -\{0\}\) હોય,તો \(242 \alpha^2=.....\)

  1. A \(1680\)
  2. B \(1681\)
  3. C \(1682\)
  4. D \(1683\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1680\)

Step-by-step Solution

Detailed explanation

\(\left(\frac{z^2+81 z-15}{z^2-3 i z-2}\right) \in R\) \(\Rightarrow 1+\frac{(11 i z-13)}{\left(z^2-3 i z-2\right)} \in R\) Put \(z=\alpha-\frac{13}{11} i\) \(\Rightarrow\left(z^2-3 i z-2\right)\) is imaginary Put \(z=x+i y\)…
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