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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

ધારો કે બે વાસ્તવિક વિધેયો \(f, g: R \rightarrow R\) એ \(f(x)=\left\{\begin{array}{cl}-|x+3| & , \quad x<0 \\ e^{x} & , \quad x \geq 0\end{array}\right.\) અને \(g(x)=\left\{\begin{array}{ll}x^{2}+k_{1} x & , \quad x<0 \\ 4 x+k_{2} & , \quad x \geq 0\end{array}\right.\),પ્રમાણે વ્યખાયિત છે,જ્યાં \(k_{1}\) અને \(k_{2}\) વાસ્તવિક અંચળાક છે.જો \((gof)\) એ \(x=0\), આગળ વિકલનીય હોય,તો \((gof)\) \((-4)+\) \((gof)\) \((4)=\dots\dots\dots\) 

  1. A \(4\left(e^{4}+1\right)\)
  2. B \(2\left(2 e ^{4}+1\right)\)
  3. C \(4 e ^{4}\)
  4. D \(2\left(2 e ^{4}-1\right)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2\left(2 e ^{4}-1\right)\)

Step-by-step Solution

Detailed explanation

\(f(x)=\left\{\begin{array}{lll}x+3 & ; & x<-3 \\ -(x+3) & ; & -3 \leq x<0 \\ e^{x} & ; & x \geq 0\end{array}\right\}\) \(g(x)=\left\{\begin{array}{lll}x^{2}+k_{1} x & ; & x<0 \\ 4 x+k_{2} & ; & x \geq 0\end{array}\right\}\)…
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