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JEE Mains · Maths · STD 11- 2. Relation and Function

ધારોકે f એવો એક વિધેય છે કે જેથી \(3 f(x)+2 f\left(\frac{m}{19 x}\right)=5 x, x \neq 0\), જ્યાં \(m=\sum_{i=1}^9(i)^2\). તો \(f(5)-f(2)=\) ___ .

  1. A -9
  2. B 36
  3. C 18
  4. D 9
Verified Solution

Answer & Solution

Correct Answer

(C) 18

Step-by-step Solution

Detailed explanation

\(m=\frac{9 \times 10 \times 19}{6}=15 \times 19\) \(3 f(x)+2 f\left(\frac{15}{x}\right)=5 x\) \(\text {Replace } x \text { by } \frac{15}{x}\) \(3 f\left(\frac{15}{x}\right)+2 f(x)=\frac{75}{x}\) \(9 f(x)-4 f(x)=15 x-\frac{150}{x}\) \(5 f(x)=15 x-\frac{150}{x}\)…
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