JEE Mains · Maths · STD 11- 2. Relation and Function
Let \(f\) be a function such that \(3 f(x)+2 f\left(\frac{m}{19 x}\right)=5 x\), \(x \neq 0\), where \(m=\sum_{i=1}^9(i)^2\). Then \(f(5)-f(2)\) is equal to
- A -9
- B 36
- C 18
- D 9
Answer & Solution
Correct Answer
(C) 18
Step-by-step Solution
Detailed explanation
\(m=\frac{9 \times 10 \times 19}{6}=15 \times 19\) \(3 f(x)+2 f\left(\frac{15}{x}\right)=5 x\) \(\text {Replace } x \text { by } \frac{15}{x}\) \(3 f\left(\frac{15}{x}\right)+2 f(x)=\frac{75}{x}\) \(9 f(x)-4 f(x)=15 x-\frac{150}{x}\) \(5 f(x)=15 x-\frac{150}{x}\)…
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