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JEE Mains · Maths · STD 12 - 9. differential equations

ધારો કે \(y=y(x)\) એ વિકલ સમીકરણ \(x\left(1-x^{2}\right) \frac{d y}{d x}+\left(3 x^{2} y-y-4 x^{3}\right)=0, x>1\) નો ઉકેલ છે, જ્યાં \(y(2)=-2\). તો \(y(3)=\).............

  1. A \(-18\)
  2. B \(-12\)
  3. C \(-6\)
  4. D \(-3\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-18\)

Step-by-step Solution

Detailed explanation

\(x\left(1-x^{2}\right) \frac{d y}{d x}+\left(3 x^{2} y-y-4 x^{3}\right)=0\) \(x\left(1-x^{2}\right) \frac{d y}{d x}+\left(3 x^{2}-1\right) y=4 x^{3}\) \(\frac{d y}{d x}+\frac{\left(3 x^{2}-1\right)}{\left(x-x^{3}\right)} y=\frac{4 x^{3}}{\left(x-x^{3}\right)}\)…
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